Doonu Singh

Mahendra Nagar, Aligarh, India - 202001

Mahendra Nagar, Aligarh, India - 202001.

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I can teach every topic very easily and make it stronger for the students. Because I have total 10 year experience in different college and universities.

Hindi Mother Tongue (Native)

English Proficient

Uptu university 2007

Bachelor of Technology (B.Tech.)

Nit warangal 2009

Master of Engineering - Master of Technology (M.E./M.Tech.)

Mahendra Nagar, Aligarh, India - 202001

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Class I-V Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class I-V Tuition

10

Fees

₹ 100 per hour

Board

CBSE, State

CBSE Subjects taught

Mathematics, Hindi, EVS, Science

Experience in School or College

I am working since 2009 in different private engineering college affiliate to different university in electrical engineering department. I can taught maths.

Taught in School or College

Yes

State Syllabus Subjects taught

Mathematics, Science

Teaching Experience in detail in Class I-V Tuition

I have 10 year experience.

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1. Which school boards of Class 1-5 do you teach for?

CBSE and State

2. Have you ever taught in any School or College?

Yes

3. Which classes do you teach?

I teach BSc Tuition, BTech Tuition, Class 10 Tuition, Class 11 Tuition, Class 12 Tuition and Class I-V Tuition Classes.

4. Do you provide a demo class?

Yes, I provide a free demo class.

5. How many years of experience do you have?

I have been teaching for 10 years.

Answered on 19/09/2019 CBSE/Class 12/Mathematics/Matrices/NCERT Solutions/Exercise 3.1

a-b= -1, 2a+c=5, 2a-b=0, & 3c+d=13 find the value b=1, a=0, c=5, d=-2

Like 0

Answers 4 Comments Answered on 19/09/2019 CBSE/Class 12/Mathematics/Continuity and Differentiability/NCERT Solutions/Exercise 5.5

Differentiate the function with respect to x. ...more

Differentiate the function with respect to *x*.

Cosx .d÷dx(cos2x.cos3x)+ cos2x d÷dx(cosx.cos3x)+ cos3x. d÷dx(cosx.cos2x). Solve and get the ans

Like 0

Answers 2 Comments Answered on 15/09/2019 CBSE/Class 12/Mathematics/Application of Derivatives/NCERT Solutions/Exercise 6.5

Answered on 15/09/2019 CBSE/Class 12/Mathematics/Application of Derivatives/NCERT Solutions/Exercise 6.5

F(-x)= -x+2-1 for maximum. X-2-1 X-2 not equal to f x. F(x)=-x+2-1=-x+1= for minimum.

Like 0

Answers 3 Comments Answered on 09/09/2019 CBSE/Class 12/Mathematics/Application of Derivatives/NCERT Solutions/Exercise 6.5

It is given that at x = 1, the function x4− 62x2 + ax + 9 attains its maximum value, on the... ...more

It is given that at *x* = 1, the function *x*^{4}− 62*x*^{2} + *ax* + 9 attains its maximum value, on the interval [0, 2]. Find the value of *a*.

Maximum value d÷dx=0 4x^3-62×2x+a+9=0 Put x=0 A=-9, Put x=3 108-372+a+9=0a=-117+372 A=287 ans

Like 0

Answers 2 Comments Class I-V Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class I-V Tuition

10

Fees

₹ 100 per hour

Board

CBSE, State

CBSE Subjects taught

Mathematics, Hindi, EVS, Science

Experience in School or College

Taught in School or College

Yes

State Syllabus Subjects taught

Mathematics, Science

Teaching Experience in detail in Class I-V Tuition

I have 10 year experience.

Class 10 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 10 Tuition

10

Board

CBSE, State

CBSE Subjects taught

Mathematics, Science

Taught in School or College

No

State Syllabus Subjects taught

EVS, Science, Mathematics

Class 11 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 11 Tuition

10

Board

CBSE, IGCSE, ISC/ICSE, State

ISC/ICSE Subjects taught

Physics, Mathematics

CBSE Subjects taught

Physics, Mathematics

IGCSE Subjects taught

Physics, Mathematics

Taught in School or College

No

State Syllabus Subjects taught

Engineering Graphics, Physics, Electronics, Logic, Mathematics, Political Science, Geology

BTech Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in BTech Tuition

10

BTech Electrical & Electronics subjects

Flexible Ac Transmission Systems, Electric Power Quality, Electrical Circuit Analysis, Modern Power Converters, High-Voltage Engineering, Electromagnetic Theory, Switchgear And Protection, Control Systems, Electrical Machinery, Electric Energy Systems, Power Generation And Economics, High-Voltage Direct Current (Hvdc) Transmission, Electric Power Stations, Power System Engineering, Electronic Measurements And Instrumentation, Traveling Waves On Transmission System, Power Electronics, Solid State Drives, Smart Grid Technologies, Microprocessors, Circuit Theory, Power System Protection, Regulation & Security, Renewable Energy, Linear And Nonlinear Systems, Linear And Digital Control Theory, Measurements & Instrumentation

BTech Branch

BTech Electrical & Electronics, BTech 1st Year Engineering

Experience in School or College

I have done b tech in electrical engineering in 2007 . I clear gate 2007 with all india rank 272. I have got admission in power system engineering in nit Warangal. M tech completed in 2009 with hons. After that since 2009 I am teaching different engineering colleges and universities all electrical engineering subject.

Type of class

Regular Classes, Crash Course

Class strength catered to

One on one/ Private Tutions, Group Classes

Taught in School or College

Yes

BTech 1st Year subjects

Basic Electrical Technology, Environmental Studies, Advanced Mathematics (M2), Basic Electronics, Engineering Mathematics (M1)

Teaching Experience in detail in BTech Tuition

I am expert in electrical engineering, power system, control system, net work system, and distribution system, electric machine. I crack gate exam 272 all india rank. I completed m tech in power system from nit Warangal. I have total 10 experience in different university.

Class 12 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 12 Tuition

10

Board

CBSE, State

CBSE Subjects taught

Physics, Mathematics

Taught in School or College

No

State Syllabus Subjects taught

Physics, Mathematics

BSc Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in BSc Tuition

10

BSc Physics Subjects

Electromagnetic Theory, Electronic Devices, Solid State Physics, Digital Electronics, Numerical Analysis

Experience in School or College

I am m tech in electrical engineering from nit warangal with hons.i have crack gate exam 2007 with all india rank 272. I have total experience 10 year since 2009 in different engineering colleges.

Type of class

Regular Classes, Crash Course

Class strength catered to

One on one/ Private Tutions, Group Classes

Taught in School or College

Yes

BSc Branch

BSc Mathematics, BSc Physics

BSc Mathematics Subjects

Differential Equations and Mathematical Modelling, Algebra, Probability and Statistics, Formal Logic, Calculus, Numerical Methods and Programming, Number Theory

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No Reviews yet! Be the first one to Review

Answered on 19/09/2019 CBSE/Class 12/Mathematics/Matrices/NCERT Solutions/Exercise 3.1

a-b= -1, 2a+c=5, 2a-b=0, & 3c+d=13 find the value b=1, a=0, c=5, d=-2

Like 0

Answers 4 Comments Answered on 19/09/2019 CBSE/Class 12/Mathematics/Continuity and Differentiability/NCERT Solutions/Exercise 5.5

Differentiate the function with respect to x. ...more

Differentiate the function with respect to *x*.

Cosx .d÷dx(cos2x.cos3x)+ cos2x d÷dx(cosx.cos3x)+ cos3x. d÷dx(cosx.cos2x). Solve and get the ans

Like 0

Answers 2 Comments

F(-x)= -x+2-1 for maximum. X-2-1 X-2 not equal to f x. F(x)=-x+2-1=-x+1= for minimum.

Like 0

Answers 3 Comments Answered on 09/09/2019 CBSE/Class 12/Mathematics/Application of Derivatives/NCERT Solutions/Exercise 6.5

It is given that at x = 1, the function x4− 62x2 + ax + 9 attains its maximum value, on the... ...more

*x* = 1, the function *x*^{4}− 62*x*^{2} + *ax* + 9 attains its maximum value, on the interval [0, 2]. Find the value of *a*.

Maximum value d÷dx=0 4x^3-62×2x+a+9=0 Put x=0 A=-9, Put x=3 108-372+a+9=0a=-117+372 A=287 ans

Like 0

Answers 2 Comments Load More

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